public
Idler roller face width
$$ l_{base} = 0.244 \:
m $$
Cross sectional area
$$ A_{conv_{5}} = {\left({ l_{base} + l_{base} \cdot \cos( \lambda_{idler1_{rad}} ) }\right) \cdot l_{base} \cdot \sin( \lambda_{idler1_{rad}} ) + \left({ l_{base} + 2 \cdot l_{base} \cdot \cos( \lambda_{idler1_{rad}} ) + {( b_{belt} - 3 \cdot l_{base} ) \over 2} \cdot \cos( \lambda_{idler2_{rad}} ) }\right) \cdot {( b_{belt} - 3 \cdot l_{base} ) \over 2} \cdot \sin( \lambda_{idler2_{rad}} ) + \left({ 0.5 \cdot l_{base} + l_{base} \cdot \cos( \lambda_{idler1_{rad}} ) + {( b_{belt} - 3 \cdot l_{base} ) \over 2} \cdot \cos( \lambda_{idler2_{rad}} ) }\right) ^ 2 \cdot \tan( \beta_{surcharge_{rad}} )} \:, m^2 $$
