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Calculations
Bending moment
This functionality is in
beta stage
.
Bending moment
public
Maximum bending moment in simply supported beam under equally spaced in the middle uniform load.
Input
Total distributed load
$ W_d = 15000 \; \; N $
Distributed load distance
$ b = 0.07 \; \; m $
Distance between load and support
$ a = 0.0225 \; \; m $
Result
$$ M_{B_{d_{max}}} = {\left({ {W_d \over 4} }\right) \cdot \left({ 2 \cdot a + b - {b \over 2} }\right)} \; \; , {Nm} $$
Show formula syntax
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M_{B_{d_{max}}} = ( W_d / 4 ) * ( 2 * a + b - b / 2 )
Dependant calculations
3
Combined bending
public
Combined maximum bending with 2 equal point loads and distributed load.
Combined bending moment
$$ M_{B_{2pd}} = {M_{B_{d_{max}}} + M_{B_2p}} \:, Nm $$
Minimum shaft diameter
public
Calculate minimum diameter of shaft subject to bending by distributed load using AS1403 formula 1 (no tension & no torsion).
Safety factor
$$ F_S = 2 \: $$ Yield stress
$$ F_Y = 300 \: MPa $$
$$ D_{shaft_{min_d}} = {\left({ {F_S \over F_Y} \cdot M_{B_{d_{max}}} \cdot 10 ^ 4 }\right) ^ \left({ {1 \over 3} }\right)} \:, mm $$
Bending stress
public
Calculate normal stress in a section, with known section modulus, due to bending caused by distributed load
Section modulus of the beam
$$ W_{y_{section}} = 10000 \: mm^3 $$
Bending stress
$$ \sigma_{bend_{d_{max}}} = {10 ^ 3 \cdot {M_{B_{d_{max}}} \over W_{y_{section}}}} \:, MPa $$
Calculation