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Euler's number
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Euler's number
$$ e = 2.71828 \: $$

Dependant calculations (3)  
Wire rope breaking force
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public
Load to be lifted
$$ P_{load} = 10.5 \: t $$ Number of rope falls
$$ n_{falls} = 2 \: $$ Safety factor
$$ s_f = 5.6 \: $$
Minimum required breaking force
$$ F_{breq} = {\left({ P_{load} \cdot g \cdot s_f }\right) \over \left({ n_{falls} \cdot \eta_{reeving} }\right)} \:, kN $$
Rope reeving efficiency
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Number of sheaves
$$ n_{sheaves} = 3 \: $$
Reeving Arrangement Efficiency
$$ \eta_{reeving} = {\eta_{sheave} ^ \left({ n_{sheaves} }\right)} $$
Rope sheave efficiency
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public
Friction coefficient of sheave bearing
$$ \mu = 0.005 \: $$ Wrap angle
$$ \theta = 3.1415 \: rad $$
Sheave efficiency
$$ \eta_{sheave} = {1 \over \left({ e ^ \left({ \mu \cdot \theta }\right) }\right)} $$
Discipline: mechanical
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