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Section modulus of RHS
public
Section modulus of square hollow section (RHS)
Section modulus
$$ W_{y_{RHS}} = {{\left({ B \cdot H ^ 3 - b \cdot h ^ 3 }\right) \over \left({ 6 \cdot H }\right)}} \; \; , {mm ^ 3} $$
CHS inside diameter
public
Calculate inside diameter of circular hollow section for given section modulus and outside diameter
Inside diameter
$$ d_{CHS_{req}} = {\left({ D ^ 4 - \left({ {32 \over \pi} \cdot W \cdot D }\right) }\right) ^ \left({ {1 \over 4} }\right)} \; \; , {mm} $$
Torsion modulus of CHS
public
Torsion modulus of circular hollow section with known diameters
Section modulus
$$ W_{t_{CHS}} = {{\pi \over 16} \cdot \left({ {\left({ D ^ 4 - d ^ 4 }\right) \over D} }\right)} \; \; , {mm ^ 3} $$
Section modulus of CHS
public
Section modulus of circular hollow section with known diameters
Section modulus
$$ W_{y_{CHS}} = {{\pi \over 32} \cdot \left({ {\left({ D ^ 4 - d ^ 4 }\right) \over D} }\right)} \; \; , {mm ^ 3} $$
Bending stress
public
Calculate normal stress in simply supported beam, with known section modulus, due to bending caused by 2 symmetrical point loads.
Bending stress
$$ \sigma_{bend_{2p}} = {10 ^ 3 \cdot {M_{B_2p} \over W_{y_{section}}}} \; \; , {MPa} $$
Moment modification factor
public
Moment modification factor for segments fully or partially restrained at both ends
Moment modification factor calculated
$$ \alpha_{m_{cal_{AS4100}}} = {1.0 + 0.35 \cdot \left({ 1 - {\left({ 2 \cdot a }\right) \over l} }\right) ^ 2} \; \; $$
Design bending moment in RHS
public
Design bending moment in RHS about the major principal axis analyzed by the elastic method as per AS4100:2020 Section 4.4.2.2
$$ M_{x_{AS4100}} = {\phi_{ls_{AS4100}} \cdot M_{b_{AS4100}}} \; \; , {Nm} $$
Gear wheel radial force
public
Radial force as a result of peripheral force in a gear wheel.
Radial force
$$ P_r = {P_h \cdot \tan\left({ \alpha_n \cdot {\pi \over 180} }\right)} \; \; , {N} $$
Combined bending in 2 planes
public
Combined bending
$$ M_{B_{comb}} = {\sqrt{ M_{B_1} ^ 2 + M_{B_2} ^ 2 }} \; \; , {Nm} $$
Gearbox output speed
public
Output speed
$$ n_2 = {{n_1 \over i}} \; \; , {rpm} $$
Shear stress
public
Calculate shear stress in a shaft due to torsion.
Shear stress
$$ \tau_{shear_{shaft}} = {{\left({ T_N \cdot 10 ^ 3 }\right) \over W_{t_{circle}}}} \; \; , {MPa} $$
Wire rope breaking force
public
Calculate minimum required breaking force of a wire rope for a given reeving arrangement and a safety factor
Required breaking force
$$ F_{rope_{breq}} = {{( P_{load} \cdot g \cdot s_f ) \over \left({ n_{falls} \cdot \eta_{reeving} }\right)}} \; \; , {kN} $$
Maximum bending deflection
public
Maximum deflection of simply supported beam subject to distributed load applied over its full length.
Maximum deflection
$$ \Delta_{max_{dis_{full}}} = {{\left({ 5 \cdot W \cdot l_{\Delta} ^ 3 }\right) \over \left({ 384 \cdot E \cdot I }\right)}} \; \; , {mm} $$
Beam length
public
Length
$$ l_{\Delta} = {a_{\Delta} + b_{\Delta}} \; \; , {mm} $$
Force from torque
public
Calculate force resulting from torque at specific distance.
Force
$$ F_{torque} = {{T \over a}} \; \; , {N} $$
Minimum shaft diameter - AS1403 F1
public
Minimum shaft diameter as per AS1403 Table 2 Formula 1
Minimum shaft diameter
$$ D_{min_{AS1403_{F1}}} = {\left({ 10 ^ 4 \cdot {F_S \over F_Y} \cdot \sqrt{ \left({ M_q + {\left({ P_q \cdot D_{try} }\right) \over 8000} }\right) ^ 2 + {3 \over 4} \cdot T_q ^ 2 } }\right) ^ \left({ {1 \over 3} }\right)} \; \; , {mm} $$
Bending moment
public
Maximum bending moment in simply supported beam under uniform load over its full length.
$$ M_{B_{d_{max_{full}}}} = {{\left({ W_d \cdot l }\right) \over 8}} \; \; , {Nm} $$
Bending stress
public
Calculate normal stress in a section, with known section modulus, due to bending caused by distributed load over its full length
Bending stress
$$ \sigma_{bend_{d_{max_{full}}}} = {10 ^ 3 \cdot {M_{B_{d_{max_{full}}}} \over W_{y_{section}}}} \; \; , {MPa} $$
Maximum bending deflection
public
Maximum deflection of simply supported beam subject to single point load applied off centre.
Maximum deflection
$$ \Delta_{max_{1P}} = {{\left({ P \cdot a_{\Delta} \cdot b_{\Delta} \cdot \left({ a_{\Delta} + 2 \cdot b_{\Delta} }\right) \cdot \sqrt{ 3 \cdot a_{\Delta} \cdot \left({ a_{\Delta} + 2 \cdot b_{\Delta} }\right) } }\right) \over \left({ 27 \cdot E \cdot I \cdot l_{\Delta} }\right)}} \; \; , {mm} $$
Bin discharge time (h)
public
Time, in hours (h), required to discharge bin with given volumetric capacity and volumetric flow rate.
Discharge time
$$ t_{bin_{discharge}} = {{V_{bin} \over Q_{vol}}} \; \; , {h} $$
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